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294 (3ij : k = i+j : i ^ exp.m A j^ exp.n) = { arithmetic } k ^ exp.m + exp.n . We have thus derived that exp.(mxn) = exp.m + exp.n. Solution 9.1. (a) Valid. (b) Invalid (the value of i is changed by the assignment). (c) Valid. (d) Invalid (a valid postcondition would be j < i).

Note When defining your hosts, one must be the primary, and another the secondary node (synchronizing from one to the other). With this in mind, the secondary node s device you are synchronizing to must be the same as or bigger than the primary s.

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We calculate m, the right side of the assignment to r, as follows. The formal requirement on m is (r = PmodQ)[P,r := 2xP + b,m] <= r = PmodQ , which is equivalent to m = (2xP + b)modQ <= r = PmodQ .

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If you have multiple devices that you want to synchronize, you can specify multiple resource definitions in the same file. For example, if you want to synchronize /dev/sdb2 to 192.168.0.5 and synchronize /dev/sdb3 to 192.168.0.6, you can specify two separate resource definitions.

When you define a host in the DRBD definition section, you must specify the node name as returned by the uname -n command. This is paramount to the operation of DRBD, and if it is incorrect, DRBD will complain at startup. Listing 26-1 is a sample DRBD configuration file for a partnership.

Now,

resource drbd0 { net { sync-max = 30M } protocol = C fsckcmd = /bin/true # DB Server on node1 { device = disk = address = port = }

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# DR DB Server on node2 { device = /dev/nb0 disk = /dev/sda8 address = 192.168.0.3 port = 7788 } }

(2xP + b)modQ { = modular addition: (15.26) } ((2xP) modQ + b) mod Q { modular multiplication: Exercise 15.27 }

We have defined two machines, node1 and node2; node1 is the primary node in the partnership (the first node defined). As synchronization takes place over the network, it is a good idea to specify how much bandwidth can be used when sending data between machines. If you have to share your network bandwidth with other applications which is usually true over a wide area network (WAN) link to a DR site you do not want to saturate your connection at the sake of one DR configuration. The net section allows you to configure any network-based operations that DRBD will use during synchronization. For example, here we have defined a maximum synchronization rate of 30 megabytes per second (Mbps) so as not to saturate our 100 Mbps link.

(2x(PmodQ) + { assume r = P mod Q } ib)modQ . That is, r = P mod Q is maintained invariant by taking m to be (2xr + b) mod Q. This still involves a 'mod Q' operation, which we must eliminate. The strategy is to split the assignment to r into the composition of two assignments, the first assigning 2xr + b to r, and the second assigning r mod Q to r, as shown below. A r - PmodQ } P,r \- 2xP + b,2xr + b ; { (KP A rmodQ = PmodQ } r := r m o d Q A r = PmodQ } . This simplifies the task to replacing the second assignment by something not involving the 'mod Q' operation. The assignment r := r m o d Q may be replaced by skip if the precondition r = r mod Q holds. Now, r = r mod Q is equivalent to O^r < Q . Also, by an easy calculation, (15.37)

A very important aspect of DRBD is the protocol used for synchronization. DRBD defines three protocols that can be used. They are listed in Table 26-1.

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